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2(x+1)=(x-5)
We move all terms to the left:
2(x+1)-((x-5))=0
We multiply parentheses
2x-((x-5))+2=0
We calculate terms in parentheses: -((x-5)), so:We get rid of parentheses
(x-5)
We get rid of parentheses
x-5
Back to the equation:
-(x-5)
2x-x+5+2=0
We add all the numbers together, and all the variables
x+7=0
We move all terms containing x to the left, all other terms to the right
x=-7
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