2(x+1)/5-1/2=3(x+2)/5

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Solution for 2(x+1)/5-1/2=3(x+2)/5 equation: 



2(x+1)/5-1/2=3(x+2)/5

We move all terms to the left:

2(x+1)/5-1/2-(3(x+2)/5)=0

We calculate fractions


(4x+4)/()+(-(3(x+2)*2)/()+()/()=0



We calculate terms in parentheses: +(-(3(x+2)*2)/()+()/(), so:

-(3(x+2)*2)/()+()/(

We add all the numbers together, and all the variables

-(3(x+2)*2)/()+1

We multiply all the terms by the denominator


-(3(x+2)*2)+1*()



We calculate terms in parentheses: -(3(x+2)*2), so:

3(x+2)*2

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

-(6x+12)

We get rid of parentheses

-6x-12

Back to the equation:

+(-6x-12)



We get rid of parentheses

(4x+4)/()-6x-12=0

We multiply all the terms by the denominator


(4x+4)-6x*()-12*()=0

We add all the numbers together, and all the variables

(4x+4)-6x*()=0

We get rid of parentheses

4x-6x*()+4=0

We move all terms containing x to the left, all other terms to the right

4x-6x*()=-4

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