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2(x+1)-3(x-2)=5(x+4)
We move all terms to the left:
2(x+1)-3(x-2)-(5(x+4))=0
We multiply parentheses
2x-3x-(5(x+4))+2+6=0
We calculate terms in parentheses: -(5(x+4)), so:We add all the numbers together, and all the variables
5(x+4)
We multiply parentheses
5x+20
Back to the equation:
-(5x+20)
-1x-(5x+20)+8=0
We get rid of parentheses
-1x-5x-20+8=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2
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