2(x+1)-3(X+2)=8x

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Solution for 2(x+1)-3(X+2)=8x equation: 



2(x+1)-3(x+2)=8x

We move all terms to the left:

2(x+1)-3(x+2)-(8x)=0

We add all the numbers together, and all the variables

-8x+2(x+1)-3(x+2)=0

We multiply parentheses

-8x+2x-3x+2-6=0

We add all the numbers together, and all the variables

-9x-4=0

We move all terms containing x to the left, all other terms to the right

-9x=4

x=4/-9

x=-4/9

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