2(x+1)+8=6(2x-4)

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Solution for 2(x+1)+8=6(2x-4) equation:



2(x+1)+8=6(2x-4)
We move all terms to the left:
2(x+1)+8-(6(2x-4))=0
We multiply parentheses
2x-(6(2x-4))+2+8=0
We calculate terms in parentheses: -(6(2x-4)), so:
6(2x-4)
We multiply parentheses
12x-24
Back to the equation:
-(12x-24)
We add all the numbers together, and all the variables
2x-(12x-24)+10=0
We get rid of parentheses
2x-12x+24+10=0
We add all the numbers together, and all the variables
-10x+34=0
We move all terms containing x to the left, all other terms to the right
-10x=-34
x=-34/-10
x=3+2/5

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