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2(x+1)+7=6x-4(-3+x)
We move all terms to the left:
2(x+1)+7-(6x-4(-3+x))=0
We add all the numbers together, and all the variables
2(x+1)-(6x-4(x-3))+7=0
We multiply parentheses
2x-(6x-4(x-3))+2+7=0
We calculate terms in parentheses: -(6x-4(x-3)), so:We add all the numbers together, and all the variables
6x-4(x-3)
We multiply parentheses
6x-4x+12
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
2x-(2x+12)+9=0
We get rid of parentheses
2x-2x-12+9=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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