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2(x+1)+4x=3(2x-2)+8
We move all terms to the left:
2(x+1)+4x-(3(2x-2)+8)=0
We add all the numbers together, and all the variables
4x+2(x+1)-(3(2x-2)+8)=0
We multiply parentheses
4x+2x-(3(2x-2)+8)+2=0
We calculate terms in parentheses: -(3(2x-2)+8), so:We add all the numbers together, and all the variables
3(2x-2)+8
We multiply parentheses
6x-6+8
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
6x-(6x+2)+2=0
We get rid of parentheses
6x-6x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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