2(x+1)+4x=3(2x+1)+8

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Solution for 2(x+1)+4x=3(2x+1)+8 equation: 


Simplifying
2(x + 1) + 4x = 3(2x + 1) + 8

Reorder the terms:
2(1 + x) + 4x = 3(2x + 1) + 8
(1 * 2 + x * 2) + 4x = 3(2x + 1) + 8
(2 + 2x) + 4x = 3(2x + 1) + 8

Combine like terms: 2x + 4x = 6x
2 + 6x = 3(2x + 1) + 8

Reorder the terms:
2 + 6x = 3(1 + 2x) + 8
2 + 6x = (1 * 3 + 2x * 3) + 8
2 + 6x = (3 + 6x) + 8

Reorder the terms:
2 + 6x = 3 + 8 + 6x

Combine like terms: 3 + 8 = 11
2 + 6x = 11 + 6x

Add '-6x' to each side of the equation.
2 + 6x + -6x = 11 + 6x + -6x

Combine like terms: 6x + -6x = 0
2 + 0 = 11 + 6x + -6x
2 = 11 + 6x + -6x

Combine like terms: 6x + -6x = 0
2 = 11 + 0
2 = 11

Solving
2 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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