2(x+1)+3-6=10(x-2)+15-5x

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Solution for 2(x+1)+3-6=10(x-2)+15-5x equation: 



2(x+1)+3-6=10(x-2)+15-5x

We move all terms to the left:

2(x+1)+3-6-(10(x-2)+15-5x)=0

We add all the numbers together, and all the variables

2(x+1)-(10(x-2)+15-5x)-3=0

We multiply parentheses

2x-(10(x-2)+15-5x)+2-3=0



We calculate terms in parentheses: -(10(x-2)+15-5x), so:

10(x-2)+15-5x

determiningTheFunctionDomain
10(x-2)-5x+15

We add all the numbers together, and all the variables

-5x+10(x-2)+15

We multiply parentheses

-5x+10x-20+15

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We add all the numbers together, and all the variables

2x-(5x-5)-1=0

We get rid of parentheses

2x-5x+5-1=0

We add all the numbers together, and all the variables

-3x+4=0

We move all terms containing x to the left, all other terms to the right

-3x=-4

x=-4/-3

x=1+1/3

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