2(x+1)+1=7-2(x-5)

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Solution for 2(x+1)+1=7-2(x-5) equation: 



2(x+1)+1=7-2(x-5)

We move all terms to the left:

2(x+1)+1-(7-2(x-5))=0

We multiply parentheses

2x-(7-2(x-5))+2+1=0



We calculate terms in parentheses: -(7-2(x-5)), so:

7-2(x-5)

determiningTheFunctionDomain
-2(x-5)+7

We multiply parentheses

-2x+10+7

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

2x-(-2x+17)+3=0

We get rid of parentheses

2x+2x-17+3=0

We add all the numbers together, and all the variables

4x-14=0

We move all terms containing x to the left, all other terms to the right

4x=14

x=14/4

x=3+1/2

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