2(x+1)+1=3(x+2)-6

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Solution for 2(x+1)+1=3(x+2)-6 equation: 



2(x+1)+1=3(x+2)-6

We move all terms to the left:

2(x+1)+1-(3(x+2)-6)=0

We multiply parentheses

2x-(3(x+2)-6)+2+1=0



We calculate terms in parentheses: -(3(x+2)-6), so:

3(x+2)-6

We multiply parentheses

3x+6-6

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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