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2(x+)-6=10-3(x-1)
We move all terms to the left:
2(x+)-6-(10-3(x-1))=0
We add all the numbers together, and all the variables
2(+x)-(10-3(x-1))-6=0
We multiply parentheses
2x-(10-3(x-1))-6=0
We calculate terms in parentheses: -(10-3(x-1)), so:We get rid of parentheses
10-3(x-1)
determiningTheFunctionDomain -3(x-1)+10
We multiply parentheses
-3x+3+10
We add all the numbers together, and all the variables
-3x+13
Back to the equation:
-(-3x+13)
2x+3x-13-6=0
We add all the numbers together, and all the variables
5x-19=0
We move all terms containing x to the left, all other terms to the right
5x=19
x=19/5
x=3+4/5
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