2(x)+1+(x)=3(x-2)+7

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Solution for 2(x)+1+(x)=3(x-2)+7 equation: 



2(x)+1+(x)=3(x-2)+7

We move all terms to the left:

2(x)+1+(x)-(3(x-2)+7)=0

We add all the numbers together, and all the variables

3x-(3(x-2)+7)+1=0



We calculate terms in parentheses: -(3(x-2)+7), so:

3(x-2)+7

We multiply parentheses

3x-6+7

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

3x-3x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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