2(w-5)=2w+4-2(-5w-1)

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Solution for 2(w-5)=2w+4-2(-5w-1) equation: 



2(w-5)=2w+4-2(-5w-1)

We move all terms to the left:

2(w-5)-(2w+4-2(-5w-1))=0

We multiply parentheses

2w-(2w+4-2(-5w-1))-10=0



We calculate terms in parentheses: -(2w+4-2(-5w-1)), so:

2w+4-2(-5w-1)

determiningTheFunctionDomain
2w-2(-5w-1)+4

We multiply parentheses

2w+10w+2+4

We add all the numbers together, and all the variables

12w+6

Back to the equation:

-(12w+6)



We get rid of parentheses

2w-12w-6-10=0

We add all the numbers together, and all the variables

-10w-16=0

We move all terms containing w to the left, all other terms to the right

-10w=16

w=16/-10

w=-1+3/5

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