2(w-1)=2w+2-2(-5w-1)

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Solution for 2(w-1)=2w+2-2(-5w-1) equation: 



2(w-1)=2w+2-2(-5w-1)

We move all terms to the left:

2(w-1)-(2w+2-2(-5w-1))=0

We multiply parentheses

2w-(2w+2-2(-5w-1))-2=0



We calculate terms in parentheses: -(2w+2-2(-5w-1)), so:

2w+2-2(-5w-1)

determiningTheFunctionDomain
2w-2(-5w-1)+2

We multiply parentheses

2w+10w+2+2

We add all the numbers together, and all the variables

12w+4

Back to the equation:

-(12w+4)



We get rid of parentheses

2w-12w-4-2=0

We add all the numbers together, and all the variables

-10w-6=0

We move all terms containing w to the left, all other terms to the right

-10w=6

w=6/-10

w=-3/5

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