2(w-1)+4w=3(w-1)+1

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Solution for 2(w-1)+4w=3(w-1)+1 equation: 



2(w-1)+4w=3(w-1)+1

We move all terms to the left:

2(w-1)+4w-(3(w-1)+1)=0

We add all the numbers together, and all the variables

4w+2(w-1)-(3(w-1)+1)=0

We multiply parentheses

4w+2w-(3(w-1)+1)-2=0



We calculate terms in parentheses: -(3(w-1)+1), so:

3(w-1)+1

We multiply parentheses

3w-3+1

We add all the numbers together, and all the variables

3w-2

Back to the equation:

-(3w-2)



We add all the numbers together, and all the variables

6w-(3w-2)-2=0

We get rid of parentheses

6w-3w+2-2=0

We add all the numbers together, and all the variables

3w=0

w=0/3

w=0

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