2(w+2)+w=-3(w-1)+6

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Solution for 2(w+2)+w=-3(w-1)+6 equation: 



2(w+2)+w=-3(w-1)+6

We move all terms to the left:

2(w+2)+w-(-3(w-1)+6)=0

We add all the numbers together, and all the variables

w+2(w+2)-(-3(w-1)+6)=0

We multiply parentheses

w+2w-(-3(w-1)+6)+4=0



We calculate terms in parentheses: -(-3(w-1)+6), so:

-3(w-1)+6

We multiply parentheses

-3w+3+6

We add all the numbers together, and all the variables

-3w+9

Back to the equation:

-(-3w+9)



We add all the numbers together, and all the variables

3w-(-3w+9)+4=0

We get rid of parentheses

3w+3w-9+4=0

We add all the numbers together, and all the variables

6w-5=0

We move all terms containing w to the left, all other terms to the right

6w=5

w=5/6

w=5/6

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