2(v-8)-1=-4(-4v+2)-2v

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Solution for 2(v-8)-1=-4(-4v+2)-2v equation: 



2(v-8)-1=-4(-4v+2)-2v

We move all terms to the left:

2(v-8)-1-(-4(-4v+2)-2v)=0

We multiply parentheses

2v-(-4(-4v+2)-2v)-16-1=0



We calculate terms in parentheses: -(-4(-4v+2)-2v), so:

-4(-4v+2)-2v

We add all the numbers together, and all the variables

-2v-4(-4v+2)

We multiply parentheses

-2v+16v-8

We add all the numbers together, and all the variables

14v-8

Back to the equation:

-(14v-8)



We add all the numbers together, and all the variables

2v-(14v-8)-17=0

We get rid of parentheses

2v-14v+8-17=0

We add all the numbers together, and all the variables

-12v-9=0

We move all terms containing v to the left, all other terms to the right

-12v=9

v=9/-12

v=-3/4

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