2(v-5)-6=-4(-4v+5)-2v

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Solution for 2(v-5)-6=-4(-4v+5)-2v equation: 



2(v-5)-6=-4(-4v+5)-2v

We move all terms to the left:

2(v-5)-6-(-4(-4v+5)-2v)=0

We multiply parentheses

2v-(-4(-4v+5)-2v)-10-6=0



We calculate terms in parentheses: -(-4(-4v+5)-2v), so:

-4(-4v+5)-2v

We add all the numbers together, and all the variables

-2v-4(-4v+5)

We multiply parentheses

-2v+16v-20

We add all the numbers together, and all the variables

14v-20

Back to the equation:

-(14v-20)



We add all the numbers together, and all the variables

2v-(14v-20)-16=0

We get rid of parentheses

2v-14v+20-16=0

We add all the numbers together, and all the variables

-12v+4=0

We move all terms containing v to the left, all other terms to the right

-12v=-4

v=-4/-12

v=1/3

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