2(v-4)=4v+4-2(-2v-2)

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Solution for 2(v-4)=4v+4-2(-2v-2) equation: 



2(v-4)=4v+4-2(-2v-2)

We move all terms to the left:

2(v-4)-(4v+4-2(-2v-2))=0

We multiply parentheses

2v-(4v+4-2(-2v-2))-8=0



We calculate terms in parentheses: -(4v+4-2(-2v-2)), so:

4v+4-2(-2v-2)

determiningTheFunctionDomain
4v-2(-2v-2)+4

We multiply parentheses

4v+4v+4+4

We add all the numbers together, and all the variables

8v+8

Back to the equation:

-(8v+8)



We get rid of parentheses

2v-8v-8-8=0

We add all the numbers together, and all the variables

-6v-16=0

We move all terms containing v to the left, all other terms to the right

-6v=16

v=16/-6

v=-2+2/3

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