2(v-4)=2v+6-2(-4v-2)

Solution for 2(v-4)=2v+6-2(-4v-2) equation:

2(v-4)=2v+6-2(-4v-2)

We move all terms to the left:

2(v-4)-(2v+6-2(-4v-2))=0

We multiply parentheses

2v-(2v+6-2(-4v-2))-8=0


We calculate terms in parentheses: -(2v+6-2(-4v-2)), so:

2v+6-2(-4v-2)

determiningTheFunctionDomain
2v-2(-4v-2)+6

We multiply parentheses

2v+8v+4+6

We add all the numbers together, and all the variables

10v+10

Back to the equation:

-(10v+10)


We get rid of parentheses

2v-10v-10-8=0

We add all the numbers together, and all the variables

-8v-18=0

We move all terms containing v to the left, all other terms to the right

-8v=18

v=18/-8

v=-2+1/4