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2(v-3)=4v+5-3(-2v-1)
We move all terms to the left:
2(v-3)-(4v+5-3(-2v-1))=0
We multiply parentheses
2v-(4v+5-3(-2v-1))-6=0
We calculate terms in parentheses: -(4v+5-3(-2v-1)), so:We get rid of parentheses
4v+5-3(-2v-1)
determiningTheFunctionDomain 4v-3(-2v-1)+5
We multiply parentheses
4v+6v+3+5
We add all the numbers together, and all the variables
10v+8
Back to the equation:
-(10v+8)
2v-10v-8-6=0
We add all the numbers together, and all the variables
-8v-14=0
We move all terms containing v to the left, all other terms to the right
-8v=14
v=14/-8
v=-1+3/4
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