2(v-1)=4+2(-3v+9)

Solution for 2(v-1)=4+2(-3v+9) equation:

2(v-1)=4+2(-3v+9)

We move all terms to the left:

2(v-1)-(4+2(-3v+9))=0

We multiply parentheses

2v-(4+2(-3v+9))-2=0


We calculate terms in parentheses: -(4+2(-3v+9)), so:

4+2(-3v+9)

determiningTheFunctionDomain
2(-3v+9)+4

We multiply parentheses

-6v+18+4

We add all the numbers together, and all the variables

-6v+22

Back to the equation:

-(-6v+22)


We get rid of parentheses

2v+6v-22-2=0

We add all the numbers together, and all the variables

8v-24=0

We move all terms containing v to the left, all other terms to the right

8v=24

v=24/8

v=3