2(v+5)=-2(5v-2)+4v

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Solution for 2(v+5)=-2(5v-2)+4v equation: 



2(v+5)=-2(5v-2)+4v

We move all terms to the left:

2(v+5)-(-2(5v-2)+4v)=0

We multiply parentheses

2v-(-2(5v-2)+4v)+10=0



We calculate terms in parentheses: -(-2(5v-2)+4v), so:

-2(5v-2)+4v

We add all the numbers together, and all the variables

4v-2(5v-2)

We multiply parentheses

4v-10v+4

We add all the numbers together, and all the variables

-6v+4

Back to the equation:

-(-6v+4)



We get rid of parentheses

2v+6v-4+10=0

We add all the numbers together, and all the variables

8v+6=0

We move all terms containing v to the left, all other terms to the right

8v=-6

v=-6/8

v=-3/4

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