2(v+2)=-2(6v-7)+6v

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Solution for 2(v+2)=-2(6v-7)+6v equation: 



2(v+2)=-2(6v-7)+6v

We move all terms to the left:

2(v+2)-(-2(6v-7)+6v)=0

We multiply parentheses

2v-(-2(6v-7)+6v)+4=0



We calculate terms in parentheses: -(-2(6v-7)+6v), so:

-2(6v-7)+6v

We add all the numbers together, and all the variables

6v-2(6v-7)

We multiply parentheses

6v-12v+14

We add all the numbers together, and all the variables

-6v+14

Back to the equation:

-(-6v+14)



We get rid of parentheses

2v+6v-14+4=0

We add all the numbers together, and all the variables

8v-10=0

We move all terms containing v to the left, all other terms to the right

8v=10

v=10/8

v=1+1/4

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