2(v+2)-2=3(v-1)+9

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Solution for 2(v+2)-2=3(v-1)+9 equation: 



2(v+2)-2=3(v-1)+9

We move all terms to the left:

2(v+2)-2-(3(v-1)+9)=0

We multiply parentheses

2v-(3(v-1)+9)+4-2=0



We calculate terms in parentheses: -(3(v-1)+9), so:

3(v-1)+9

We multiply parentheses

3v-3+9

We add all the numbers together, and all the variables

3v+6

Back to the equation:

-(3v+6)



We add all the numbers together, and all the variables

2v-(3v+6)+2=0

We get rid of parentheses

2v-3v-6+2=0

We add all the numbers together, and all the variables

-1v-4=0

We move all terms containing v to the left, all other terms to the right

-v=4

v=4/-1

v=-4

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