2(v+2)+-v=3(v-1)+9

Solution for 2(v+2)+-v=3(v-1)+9 equation:

2(v+2)+-v=3(v-1)+9

We move all terms to the left:

2(v+2)+-v-(3(v-1)+9)=0

We add all the numbers together, and all the variables

-1v+2(v+2)-(3(v-1)+9)=0

We multiply parentheses

-1v+2v-(3(v-1)+9)+4=0


We calculate terms in parentheses: -(3(v-1)+9), so:

3(v-1)+9

We multiply parentheses

3v-3+9

We add all the numbers together, and all the variables

3v+6

Back to the equation:

-(3v+6)


We add all the numbers together, and all the variables

v-(3v+6)+4=0

We get rid of parentheses

v-3v-6+4=0

We add all the numbers together, and all the variables

-2v-2=0

We move all terms containing v to the left, all other terms to the right

-2v=2

v=2/-2

v=-1