2(v+1)=4v=3(2v-1)+8

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Solution for 2(v+1)=4v=3(2v-1)+8 equation: 



2(v+1)=4v=3(2v-1)+8

We move all terms to the left:

2(v+1)-(4v)=0

We add all the numbers together, and all the variables

-4v+2(v+1)=0

We multiply parentheses

-4v+2v+2=0

We add all the numbers together, and all the variables

-2v+2=0

We move all terms containing v to the left, all other terms to the right

-2v=-2

v=-2/-2

v=1

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