2(v+1)-4v=3(2v-1)+8

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Solution for 2(v+1)-4v=3(2v-1)+8 equation: 



2(v+1)-4v=3(2v-1)+8

We move all terms to the left:

2(v+1)-4v-(3(2v-1)+8)=0

We add all the numbers together, and all the variables

-4v+2(v+1)-(3(2v-1)+8)=0

We multiply parentheses

-4v+2v-(3(2v-1)+8)+2=0



We calculate terms in parentheses: -(3(2v-1)+8), so:

3(2v-1)+8

We multiply parentheses

6v-3+8

We add all the numbers together, and all the variables

6v+5

Back to the equation:

-(6v+5)



We add all the numbers together, and all the variables

-2v-(6v+5)+2=0

We get rid of parentheses

-2v-6v-5+2=0

We add all the numbers together, and all the variables

-8v-3=0

We move all terms containing v to the left, all other terms to the right

-8v=3

v=3/-8

v=-3/8

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