2(v+1)+4v=3(v-1)+7

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Solution for 2(v+1)+4v=3(v-1)+7 equation: 



2(v+1)+4v=3(v-1)+7

We move all terms to the left:

2(v+1)+4v-(3(v-1)+7)=0

We add all the numbers together, and all the variables

4v+2(v+1)-(3(v-1)+7)=0

We multiply parentheses

4v+2v-(3(v-1)+7)+2=0



We calculate terms in parentheses: -(3(v-1)+7), so:

3(v-1)+7

We multiply parentheses

3v-3+7

We add all the numbers together, and all the variables

3v+4

Back to the equation:

-(3v+4)



We add all the numbers together, and all the variables

6v-(3v+4)+2=0

We get rid of parentheses

6v-3v-4+2=0

We add all the numbers together, and all the variables

3v-2=0

We move all terms containing v to the left, all other terms to the right

3v=2

v=2/3

v=2/3

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