2(v+1)+4v=3(2x-1)+8

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Solution for 2(v+1)+4v=3(2x-1)+8 equation:


Simplifying
2(v + 1) + 4v = 3(2x + -1) + 8

Reorder the terms:
2(1 + v) + 4v = 3(2x + -1) + 8
(1 * 2 + v * 2) + 4v = 3(2x + -1) + 8
(2 + 2v) + 4v = 3(2x + -1) + 8

Combine like terms: 2v + 4v = 6v
2 + 6v = 3(2x + -1) + 8

Reorder the terms:
2 + 6v = 3(-1 + 2x) + 8
2 + 6v = (-1 * 3 + 2x * 3) + 8
2 + 6v = (-3 + 6x) + 8

Reorder the terms:
2 + 6v = -3 + 8 + 6x

Combine like terms: -3 + 8 = 5
2 + 6v = 5 + 6x

Solving
2 + 6v = 5 + 6x

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6v = 5 + -2 + 6x

Combine like terms: 2 + -2 = 0
0 + 6v = 5 + -2 + 6x
6v = 5 + -2 + 6x

Combine like terms: 5 + -2 = 3
6v = 3 + 6x

Divide each side by '6'.
v = 0.5 + x

Simplifying
v = 0.5 + x

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