2(v+1)+4v=2(2v-1)+8

Solution for 2(v+1)+4v=2(2v-1)+8 equation:

Simplifying
2(v + 1) + 4v = 2(2v + -1) + 8

Reorder the terms:
2(1 + v) + 4v = 2(2v + -1) + 8
(1 * 2 + v * 2) + 4v = 2(2v + -1) + 8
(2 + 2v) + 4v = 2(2v + -1) + 8

Combine like terms: 2v + 4v = 6v
2 + 6v = 2(2v + -1) + 8

Reorder the terms:
2 + 6v = 2(-1 + 2v) + 8
2 + 6v = (-1 * 2 + 2v * 2) + 8
2 + 6v = (-2 + 4v) + 8

Reorder the terms:
2 + 6v = -2 + 8 + 4v

Combine like terms: -2 + 8 = 6
2 + 6v = 6 + 4v

Solving
2 + 6v = 6 + 4v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-4v' to each side of the equation.
2 + 6v + -4v = 6 + 4v + -4v

Combine like terms: 6v + -4v = 2v
2 + 2v = 6 + 4v + -4v

Combine like terms: 4v + -4v = 0
2 + 2v = 6 + 0
2 + 2v = 6

Add '-2' to each side of the equation.
2 + -2 + 2v = 6 + -2

Combine like terms: 2 + -2 = 0
0 + 2v = 6 + -2
2v = 6 + -2

Combine like terms: 6 + -2 = 4
2v = 4

Divide each side by '2'.
v = 2

Simplifying
v = 2