2(u-6)-5=-5(-5u+4)-5u

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Solution for 2(u-6)-5=-5(-5u+4)-5u equation: 



2(u-6)-5=-5(-5u+4)-5u

We move all terms to the left:

2(u-6)-5-(-5(-5u+4)-5u)=0

We multiply parentheses

2u-(-5(-5u+4)-5u)-12-5=0



We calculate terms in parentheses: -(-5(-5u+4)-5u), so:

-5(-5u+4)-5u

We add all the numbers together, and all the variables

-5u-5(-5u+4)

We multiply parentheses

-5u+25u-20

We add all the numbers together, and all the variables

20u-20

Back to the equation:

-(20u-20)



We add all the numbers together, and all the variables

2u-(20u-20)-17=0

We get rid of parentheses

2u-20u+20-17=0

We add all the numbers together, and all the variables

-18u+3=0

We move all terms containing u to the left, all other terms to the right

-18u=-3

u=-3/-18

u=1/6

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