2(u-5)-3=-3(-8u+7)-6u

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Solution for 2(u-5)-3=-3(-8u+7)-6u equation: 



2(u-5)-3=-3(-8u+7)-6u

We move all terms to the left:

2(u-5)-3-(-3(-8u+7)-6u)=0

We multiply parentheses

2u-(-3(-8u+7)-6u)-10-3=0



We calculate terms in parentheses: -(-3(-8u+7)-6u), so:

-3(-8u+7)-6u

We add all the numbers together, and all the variables

-6u-3(-8u+7)

We multiply parentheses

-6u+24u-21

We add all the numbers together, and all the variables

18u-21

Back to the equation:

-(18u-21)



We add all the numbers together, and all the variables

2u-(18u-21)-13=0

We get rid of parentheses

2u-18u+21-13=0

We add all the numbers together, and all the variables

-16u+8=0

We move all terms containing u to the left, all other terms to the right

-16u=-8

u=-8/-16

u=1/2

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