2(u-4)=4u+1-2(-2u-3)

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Solution for 2(u-4)=4u+1-2(-2u-3) equation: 



2(u-4)=4u+1-2(-2u-3)

We move all terms to the left:

2(u-4)-(4u+1-2(-2u-3))=0

We multiply parentheses

2u-(4u+1-2(-2u-3))-8=0



We calculate terms in parentheses: -(4u+1-2(-2u-3)), so:

4u+1-2(-2u-3)

determiningTheFunctionDomain
4u-2(-2u-3)+1

We multiply parentheses

4u+4u+6+1

We add all the numbers together, and all the variables

8u+7

Back to the equation:

-(8u+7)



We get rid of parentheses

2u-8u-7-8=0

We add all the numbers together, and all the variables

-6u-15=0

We move all terms containing u to the left, all other terms to the right

-6u=15

u=15/-6

u=-2+1/2

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