2(u-3)=3(u+4)-(u-6)

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Solution for 2(u-3)=3(u+4)-(u-6) equation: 



2(u-3)=3(u+4)-(u-6)

We move all terms to the left:

2(u-3)-(3(u+4)-(u-6))=0

We multiply parentheses

2u-(3(u+4)-(u-6))-6=0



We calculate terms in parentheses: -(3(u+4)-(u-6)), so:

3(u+4)-(u-6)

We multiply parentheses

3u-(u-6)+12

We get rid of parentheses

3u-u+6+12

We add all the numbers together, and all the variables

2u+18

Back to the equation:

-(2u+18)



We get rid of parentheses

2u-2u-18-6=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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