2(u-2)=8u+1-3(-2u-3)

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Solution for 2(u-2)=8u+1-3(-2u-3) equation: 



2(u-2)=8u+1-3(-2u-3)

We move all terms to the left:

2(u-2)-(8u+1-3(-2u-3))=0

We multiply parentheses

2u-(8u+1-3(-2u-3))-4=0



We calculate terms in parentheses: -(8u+1-3(-2u-3)), so:

8u+1-3(-2u-3)

determiningTheFunctionDomain
8u-3(-2u-3)+1

We multiply parentheses

8u+6u+9+1

We add all the numbers together, and all the variables

14u+10

Back to the equation:

-(14u+10)



We get rid of parentheses

2u-14u-10-4=0

We add all the numbers together, and all the variables

-12u-14=0

We move all terms containing u to the left, all other terms to the right

-12u=14

u=14/-12

u=-1+1/6

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