2(u+9)=-2(7u-3)+7u

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Solution for 2(u+9)=-2(7u-3)+7u equation: 



2(u+9)=-2(7u-3)+7u

We move all terms to the left:

2(u+9)-(-2(7u-3)+7u)=0

We multiply parentheses

2u-(-2(7u-3)+7u)+18=0



We calculate terms in parentheses: -(-2(7u-3)+7u), so:

-2(7u-3)+7u

We add all the numbers together, and all the variables

7u-2(7u-3)

We multiply parentheses

7u-14u+6

We add all the numbers together, and all the variables

-7u+6

Back to the equation:

-(-7u+6)



We get rid of parentheses

2u+7u-6+18=0

We add all the numbers together, and all the variables

9u+12=0

We move all terms containing u to the left, all other terms to the right

9u=-12

u=-12/9

u=-1+1/3

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