2(u+4)=-3(6u-2)+2u

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Solution for 2(u+4)=-3(6u-2)+2u equation: 



2(u+4)=-3(6u-2)+2u

We move all terms to the left:

2(u+4)-(-3(6u-2)+2u)=0

We multiply parentheses

2u-(-3(6u-2)+2u)+8=0



We calculate terms in parentheses: -(-3(6u-2)+2u), so:

-3(6u-2)+2u

We add all the numbers together, and all the variables

2u-3(6u-2)

We multiply parentheses

2u-18u+6

We add all the numbers together, and all the variables

-16u+6

Back to the equation:

-(-16u+6)



We get rid of parentheses

2u+16u-6+8=0

We add all the numbers together, and all the variables

18u+2=0

We move all terms containing u to the left, all other terms to the right

18u=-2

u=-2/18

u=-1/9

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