2(u+2)+u=3(u-1)6

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Solution for 2(u+2)+u=3(u-1)6 equation: 



2(u+2)+u=3(u-1)6

We move all terms to the left:

2(u+2)+u-(3(u-1)6)=0

We add all the numbers together, and all the variables

u+2(u+2)-(3(u-1)6)=0

We multiply parentheses

u+2u-(3(u-1)6)+4=0



We calculate terms in parentheses: -(3(u-1)6), so:

3(u-1)6

We multiply parentheses

18u-18

Back to the equation:

-(18u-18)



We add all the numbers together, and all the variables

3u-(18u-18)+4=0

We get rid of parentheses

3u-18u+18+4=0

We add all the numbers together, and all the variables

-15u+22=0

We move all terms containing u to the left, all other terms to the right

-15u=-22

u=-22/-15

u=1+7/15

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