2(u+1)=4u+16

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Solution for 2(u+1)=4u+16 equation: 



2(u+1)=4u+16

We move all terms to the left:

2(u+1)-(4u+16)=0

We multiply parentheses

2u-(4u+16)+2=0

We get rid of parentheses

2u-4u-16+2=0

We add all the numbers together, and all the variables

-2u-14=0

We move all terms containing u to the left, all other terms to the right

-2u=14

u=14/-2

u=-7

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