2(u+1)+7=3(u+2)+2u

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Solution for 2(u+1)+7=3(u+2)+2u equation: 



2(u+1)+7=3(u+2)+2u

We move all terms to the left:

2(u+1)+7-(3(u+2)+2u)=0

We multiply parentheses

2u-(3(u+2)+2u)+2+7=0



We calculate terms in parentheses: -(3(u+2)+2u), so:

3(u+2)+2u

We add all the numbers together, and all the variables

2u+3(u+2)

We multiply parentheses

2u+3u+6

We add all the numbers together, and all the variables

5u+6

Back to the equation:

-(5u+6)



We add all the numbers together, and all the variables

2u-(5u+6)+9=0

We get rid of parentheses

2u-5u-6+9=0

We add all the numbers together, and all the variables

-3u+3=0

We move all terms containing u to the left, all other terms to the right

-3u=-3

u=-3/-3

u=1

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