2(u+1)+5u=3(u+1)-2

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Solution for 2(u+1)+5u=3(u+1)-2 equation: 



2(u+1)+5u=3(u+1)-2

We move all terms to the left:

2(u+1)+5u-(3(u+1)-2)=0

We add all the numbers together, and all the variables

5u+2(u+1)-(3(u+1)-2)=0

We multiply parentheses

5u+2u-(3(u+1)-2)+2=0



We calculate terms in parentheses: -(3(u+1)-2), so:

3(u+1)-2

We multiply parentheses

3u+3-2

We add all the numbers together, and all the variables

3u+1

Back to the equation:

-(3u+1)



We add all the numbers together, and all the variables

7u-(3u+1)+2=0

We get rid of parentheses

7u-3u-1+2=0

We add all the numbers together, and all the variables

4u+1=0

We move all terms containing u to the left, all other terms to the right

4u=-1

u=-1/4

u=-1/4

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