2(t-5)-3(2t-1)=3(4t-3)-7(t-2)

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Solution for 2(t-5)-3(2t-1)=3(4t-3)-7(t-2) equation: 



2(t-5)-3(2t-1)=3(4t-3)-7(t-2)

We move all terms to the left:

2(t-5)-3(2t-1)-(3(4t-3)-7(t-2))=0

We multiply parentheses

2t-6t-(3(4t-3)-7(t-2))-10+3=0



We calculate terms in parentheses: -(3(4t-3)-7(t-2)), so:

3(4t-3)-7(t-2)

We multiply parentheses

12t-7t-9+14

We add all the numbers together, and all the variables

5t+5

Back to the equation:

-(5t+5)



We add all the numbers together, and all the variables

-4t-(5t+5)-7=0

We get rid of parentheses

-4t-5t-5-7=0

We add all the numbers together, and all the variables

-9t-12=0

We move all terms containing t to the left, all other terms to the right

-9t=12

t=12/-9

t=-1+1/3

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