2(t-3)-3(t-2)=28

Solution for 2(t-3)-3(t-2)=28 equation:

Simplifying
2(t + -3) + -3(t + -2) = 28

Reorder the terms:
2(-3 + t) + -3(t + -2) = 28
(-3 * 2 + t * 2) + -3(t + -2) = 28
(-6 + 2t) + -3(t + -2) = 28

Reorder the terms:
-6 + 2t + -3(-2 + t) = 28
-6 + 2t + (-2 * -3 + t * -3) = 28
-6 + 2t + (6 + -3t) = 28

Reorder the terms:
-6 + 6 + 2t + -3t = 28

Combine like terms: -6 + 6 = 0
0 + 2t + -3t = 28
2t + -3t = 28

Combine like terms: 2t + -3t = -1t
-1t = 28

Solving
-1t = 28

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Divide each side by '-1'.
t = -28

Simplifying
t = -28