2(t-3)+4(t-2)=28

Solution for 2(t-3)+4(t-2)=28 equation:

Simplifying
2(t + -3) + 4(t + -2) = 28

Reorder the terms:
2(-3 + t) + 4(t + -2) = 28
(-3 * 2 + t * 2) + 4(t + -2) = 28
(-6 + 2t) + 4(t + -2) = 28

Reorder the terms:
-6 + 2t + 4(-2 + t) = 28
-6 + 2t + (-2 * 4 + t * 4) = 28
-6 + 2t + (-8 + 4t) = 28

Reorder the terms:
-6 + -8 + 2t + 4t = 28

Combine like terms: -6 + -8 = -14
-14 + 2t + 4t = 28

Combine like terms: 2t + 4t = 6t
-14 + 6t = 28

Solving
-14 + 6t = 28

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 6t = 28 + 14

Combine like terms: -14 + 14 = 0
0 + 6t = 28 + 14
6t = 28 + 14

Combine like terms: 28 + 14 = 42
6t = 42

Divide each side by '6'.
t = 7

Simplifying
t = 7