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2(t-3)+2=2(2t-6)
We move all terms to the left:
2(t-3)+2-(2(2t-6))=0
We multiply parentheses
2t-(2(2t-6))-6+2=0
We calculate terms in parentheses: -(2(2t-6)), so:We add all the numbers together, and all the variables
2(2t-6)
We multiply parentheses
4t-12
Back to the equation:
-(4t-12)
2t-(4t-12)-4=0
We get rid of parentheses
2t-4t+12-4=0
We add all the numbers together, and all the variables
-2t+8=0
We move all terms containing t to the left, all other terms to the right
-2t=-8
t=-8/-2
t=+4
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