2(t-1)-3(3t-1)=2-5(6t+1)

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Solution for 2(t-1)-3(3t-1)=2-5(6t+1) equation: 



2(t-1)-3(3t-1)=2-5(6t+1)

We move all terms to the left:

2(t-1)-3(3t-1)-(2-5(6t+1))=0

We multiply parentheses

2t-9t-(2-5(6t+1))-2+3=0



We calculate terms in parentheses: -(2-5(6t+1)), so:

2-5(6t+1)

determiningTheFunctionDomain
-5(6t+1)+2

We multiply parentheses

-30t-5+2

We add all the numbers together, and all the variables

-30t-3

Back to the equation:

-(-30t-3)



We add all the numbers together, and all the variables

-7t-(-30t-3)+1=0

We get rid of parentheses

-7t+30t+3+1=0

We add all the numbers together, and all the variables

23t+4=0

We move all terms containing t to the left, all other terms to the right

23t=-4

t=-4/23

t=-4/23

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