2(t+2)=5(t+3)+14

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Solution for 2(t+2)=5(t+3)+14 equation:



2(t+2)=5(t+3)+14
We move all terms to the left:
2(t+2)-(5(t+3)+14)=0
We multiply parentheses
2t-(5(t+3)+14)+4=0
We calculate terms in parentheses: -(5(t+3)+14), so:
5(t+3)+14
We multiply parentheses
5t+15+14
We add all the numbers together, and all the variables
5t+29
Back to the equation:
-(5t+29)
We get rid of parentheses
2t-5t-29+4=0
We add all the numbers together, and all the variables
-3t-25=0
We move all terms containing t to the left, all other terms to the right
-3t=25
t=25/-3
t=-8+1/3

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