2(t+1)-3(t-1)=

Solution for 2(t+1)-3(t-1)= equation:

Simplifying
2(t + 1) + -3(t + -1) = 0

Reorder the terms:
2(1 + t) + -3(t + -1) = 0
(1 * 2 + t * 2) + -3(t + -1) = 0
(2 + 2t) + -3(t + -1) = 0

Reorder the terms:
2 + 2t + -3(-1 + t) = 0
2 + 2t + (-1 * -3 + t * -3) = 0
2 + 2t + (3 + -3t) = 0

Reorder the terms:
2 + 3 + 2t + -3t = 0

Combine like terms: 2 + 3 = 5
5 + 2t + -3t = 0

Combine like terms: 2t + -3t = -1t
5 + -1t = 0

Solving
5 + -1t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1t = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1t = 0 + -5
-1t = 0 + -5

Combine like terms: 0 + -5 = -5
-1t = -5

Divide each side by '-1'.
t = 5

Simplifying
t = 5